What total mass must you hang from the spring to stretch it to a total length of 25.0 cm ?

Question

An unstretched spring is 18.0 cm long. When you hang an 665 g weight from it, it stretches to a length of 21.0cm .

Answer 1

We know that

F=-k y

k - spring constant
y - amount the spring was stretched when force F was applied

m1g= - k y
m1=-k y/g

k=-W / (y1-y2)
k=-mg / (y1-y2)

finally
m1= y m g / [g (y1-y2)]
m1= y m / [ (y1-y2)]
m1=(25.0 -18.0) x 665 / (21.0 - 18.0)

m1= 1550 g

Answer 2

i think of the guy above me is incorrect because of the fact he says that the spring stretches 19cm even however that's at relax at 17 cm and in basic terms stretches 2cm. and then it stretches in basic terms 6cm to the 23cm mark i'm going to swap the respond he gave you because of the fact's laid out of course. first we hit upon spring consistent ok in SI units x=0.02m m=0.635kg F=kx ok=F/x ok=mg/x ok=(0.635)(9.8)/(0.02) ok=311.15 now we for given length x' =0.06m the above relation takes the variety m=kx'/g m=(311.15)(0.06)/(9.8) m=a million.905 kg or m=a million,905 g From my lab experiments this intuitively seems marvelous, in case you hung 635 g from a spring and it in basic terms stretched 2cm then that spring is stiff as hell. I thank the previous guy for doing all the artwork for which I in basic terms replaced some numbers, i exchange into attempting to artwork this out and alter into suffering earlier each and every thing.