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How would I draw 1-chloro-1-ethylcyclopentane?

2007-09-20 10:47:25 · 3 answers · asked by james_hndrsn 1 in Science & Mathematics Chemistry

3 answers

Ah, good old organic naming.

I always start at the back of the name and work forward to the front.

ending: -ane This means there are only single bonds present. Easy enough.

-pentane This means there is a 5 carbon chain with the bonds mentioned

-cyclopentane This menas those 5 carbons are in a ring shape.

This is where I would start then. Draw the 5 carbons in a ring. Should look like a pentagon.

Next 2 things are the additional things coming off of the ring.

1-ethyl: Means there is a CH2CH3 group coming off one of the carbons.

1-chloro: Means there is a Cl coming off the same carbon as the CH2CH3.

In the end, you'll get a structure that has a Cl and a CH2CH3 coming off one carbon in a 5 member ring. The other carbons are understood to have hydrogens around them to fill their 4 available bonding sites.

2007-09-20 10:58:28 · answer #1 · answered by lhvinny 7 · 1 0

Yeah, I'm not drawing that here. But it should be a 5 carbon ring (cyclopentane) with one carbon in the ring having both a Cl and a 2 carbon chain (ethyl) attached to it. And of course, the requisite hydrogens to fill it out.

2007-09-20 18:00:39 · answer #2 · answered by Wendy M 2 · 0 0

You can find the structure of 1-chloro-1-ethylcyclopentane on p. 106 of this document (Practice Problem 4.1): http://www.wadsworthmedia.com/marketing/sample_chapters/0495012033_ch04.pdf .

2007-09-20 17:55:12 · answer #3 · answered by Ketone 3 · 0 0

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