physics question?

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Suppose an astronaut drops a feather from 1.2 m above the surface of the Moon. If the acceleration due to gravity on the Moon is 1.62 m/s^2 downward, how long does it take the feather to hit the Moon's surface?

Please show work!

2007-09-20 10:36:30 · 3 answers · asked by cahill_hooker 2 in Science & Mathematics ➔ Physics

3 answers

Still Earth or Moon
h=0.5at^2

t=sqt(2h/a)
t=sqrt (2 x1.2 / 1.62)
t=1.22 sec

2007-09-20 10:40:20 · answer #1 · answered by Edward 7 · 0⤊ 0⤋

s = 1.2 m
a = 1.62 m/s^2
u = 0 m/s

v^2 = u^2 + 2as

v = u + at

2007-09-20 17:41:38 · answer #2 · answered by 4 · 0⤊ 0⤋

s=ut +1/2gt^2
1.2=1/2x1.62t^2
t^2=1.2
t=1.2^1/2
t=1s

2007-09-20 17:51:50 · answer #3 · answered by blessing o 1 · 0⤊ 0⤋