Ed was fired out of a cannon w/ a speed of 24 m/s at angle of 40 degrees to horiz.?

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Ed was fired out of a cannon w/ a speed of 24 m/s at angle of 40 degrees to horiz.?

If he landed 56.6 m away at the same hiehgt at which he was fired, how long was he in the air?

If you could show all your work it'd be greatly appreciated!! =)

2007-09-20 10:36:02 · 2 answers · asked by xplozno8 2 in Science & Mathematics ➔ Physics

2 answers

this is a range question

u = 24
a_y = - g

u_x = u cos θ

u_y = u sin θ

T = 2u sin θ / g

http://answers.yahoo.com/question/index;_ylt=AuIborpClpI2qqvDgWRzNrUjzKIX;_ylv=3?qid=20070913064229AAUdx9b

2007-09-20 10:46:12 · answer #1 · answered by 4 · 0⤊ 0⤋

I did no such thing!

If I did I would compute total time as

t=S/Vh= 56.6/(24 cos(40))=3.08 s

Why? The horizontal component of the velocity remains constant thought the flight. And the horizontal component is
Vh=v cos(40)

2007-09-20 17:49:51 · answer #2 · answered by Edward 7 · 1⤊ 0⤋