A cyclist maintains a constant velocity of
6:7 m=s headed away from point A. At some
initial time, the cyclist is 253 m from point A.
What will be his displacement from his
starting position after 81 s? Answer in units
of m
What will be his position from point A after
that time? Answer in units of m.
2007-09-20 10:30:53 · 3 answers · asked by Jarod S 2 in Science & Mathematics ➔ Physics
1. D=vt
D=6.7m/s 81= 542 m away from point A
2. Dt=D+253=796 away from point A
2007-09-20 10:38:15 · answer #1 · answered by Edward 7 · 0⤊ 1⤋
come on jarod -
6.7 m/sec * 81 sec = 542.7 meters
542.7m + 235m = 777.7 meters
2007-09-20 17:37:20 · answer #2 · answered by College Guy 2 · 0⤊ 0⤋
on the grounds that this could be your homework question i refuse to answer :P
2007-09-20 17:35:35 · answer #3 · answered by danbakuk 2 · 0⤊ 1⤋