Chem Problem help plz?

Question

According to the following reaction, how many moles of silver nitrate are necessary to form 0.689 moles iron(II) nitrate?

iron(II) chloride (aq) + silver nitrate (aq) iron(II) nitrate (aq) + silver chloride (s)


thank you very much

Answer 1

First you have to balance the equation:
FeCl2 + 2 AgNO3 ->2 AgCl(ppt)+ Fe(NO3)2
From this, 2 moles of silver nitrate will form 1 mole of the ferrous nitrate. So by proportion, 1.378 moles AgNO3 are needed to form 0.689 moles.