Finding the discriminant?

Question

I don't even know what to do with this problem!! Please help me....

x^2+2x+1=0

and the choices are
1. 0;1 real solution
2. -4, no real solutions
3. 4;2 unequal real solutions

I appreciate any and all help. First with the most helpful answer gets my vote for best answer :P

Thanks PMP, you rock!

Answer 1

x^2 + 2x + 1 = (x +1)(x + 1)

The solution is a double root at -1.

Answer 2

x^2+2x+1=0 ax^2+bx+c

Discriminate = b^2-4ac

Discriminate = 4-4 = 0

1. 0;1 real solution

Answer 3

The discriminant of a quadratic equation (ax^2 + bx + c) is:
b^2 - 4ac.

So the discriminant for your equation is: (2)^2 - 4(1)(1) = 0.

Since it's zero, you'll have 2 coincident real roots (both answers are the same).

When you factor your equation, you get:
(x+1)(x+1) = 0,
so x = -1 (both times).

Therefore, your answer is #1.

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