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Assuming that acid rain contains 4.00×10^−5 M H2So4 , approximately what volume of rain is necessary to dissolve a 230 marble statue?

2007-09-20 08:34:47 · 1 answers · asked by stranger 1 in Science & Mathematics Chemistry

1 answers

Atomic weights: Ca=40 C=12 O=16 CaCO3=100

Let marble be called M.

230lbM x 1000gM/2.2lbM x 1molM/100gM x 1molH2SO4/1molM x 1LH2SO4/4.00x10^-5molH2SO4 = 2.61 x 10^7 L rain.

2007-09-20 08:49:36 · answer #1 · answered by steve_geo1 7 · 0 0

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