finding the median please helpppppp =)?

Question

The ages of the eight-member school board are listed below.

28, 40, 34, 46, 60, 34, 51, 57

If A is equal to the median age of the group and B is equal to the mode of the group/s age, what is the value of A-B?

6
7
8
9
10

Answer 1

You should start by arranging the numbers in order to help you find the median:

28, 34, 34, 40, 46, 51, 57, 60

There are 8 values, so the median is defined as the two middle numbers averaged:

median = (46 + 40) / 2 = 43

The mode is the value that occurs most frequently, in this case it would be 34.

So, the median (A) - the mode (B) = 43 - 34 = 9.

Answer 2

YOU WANT TO FIND A - B

WHERE A = MEDIAN AGE
AND B = THE MODE...

THE AGES WERE.... 28, 40, 34, 46, 60, 34, 51, 57

SO FIRST LETS FIND THE MEDIAN (A)

FIRST PUT THE NUMBERS IN ORDER LEAST TO GREATEST...

28, 34, 34, 40, 46, 51, 57, 60

NOW FIND THE MIDDLE NUMBER...

40 AND 46 BOTH FALL IN THE MIDDLE SO AVERAGE THEM...

(40 + 46)/2 = (86)/2 = 43

SO A = 43

NOW FIND THE MODE... WHICH NUMBER OCCURS THE MOST...

34 OCCURS THE MOST SO

B= 34

NOW FIND A - B...

A - B = 43 - 34 = 9

YOUR ANSWER IS 9... (THE FOURTH CHOICE)

Answer 3

(1). *Place the numbers in order from least to greatest.

28, 34, 34, 40, 46, 51, 57, 60

First: there isn't just 1 middle number > add the middle two numbers & divide it by 2 (the quantity of the middle numbers).

(40+46)/2
86/2
43

(2). *The mode is a number repeated more than once - in this case, the mode is 34.

A > Median = 43
B > mode = 34

A - B > 43 - 34 = 9

Answer 4

Put them in order:

28, 34, 34, 40, 46, 51, 57

median - middle value. There are 8 so average the middle 2.

40 + 46 = 86 /2 = 43

mode - the most common value

34

43 - 34 = 9

Answer 5

9

Answer 6

9

Answer 7

MEDIAN WHAT 43
MODE 34

43-34=9