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2007-09-20 07:39:53 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

The fourth answer: xaz^2/2y

2007-09-20 07:44:25 · answer #1 · answered by Steve C 7 · 0 0

Just cancel all the variables and the exponents:

(2x^3y^4z^3a^2)/(4x^2y^5za)

in the numerator, the 2 gets canceled by the 4 in the denominator leaving 2 in the denominator, the x^3 can be canceled to plain x by the x^2 in the denominator, the y^4 gets canceled by the Y^5 in the denominator leaving y in the denominator, the z^3 gets reduced to z^2 by the z in the denominator, and the a^2 gets reduced to a by the a in the denominator.

so you are left with the answer of (xz^2a)/(2y)

2007-09-20 14:54:54 · answer #2 · answered by remowlms 7 · 0 0

xz^2a/2y

since this is a division, you can "subtract" the exponents of each variable from the other. example x^6/x^3 = x^3; x^4/x^7 = 1/x^3. you can do this only for the same variables. ex. x^3y^4/x^7z^5= y^4/x^3z^5

2007-09-20 14:46:54 · answer #3 · answered by alb_4 3 · 0 0

It's the first one: xz^2a/2y All you have to do is divide them.
2/4 = 1/2 ;
X^3/X^2= X ....you do the same for all of them

2007-09-20 14:47:32 · answer #4 · answered by Sarah 3 · 0 0

answer is (x.z^2.a)/2y
i couldnt understand where u are confused

2007-09-20 14:44:25 · answer #5 · answered by shuaib 2 · 0 0

hgerherwefwfww

2014-06-11 13:34:15 · answer #6 · answered by Anonymous · 0 0

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