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10 answers

http://sidney.heartland.net/courtney/java/temperature/
that`s the link you can use to convert.

in long hand C=5 /9 (F-32 )
Kelvin just add 273 (constant) to the Celsius.

68°F.....
°C = 5 (68-32) ÷ 9
= 5 (36 ) ÷ 9
= 180 ÷ 9
°C= 20.

20.° C + 273 = 293.°K

2007-09-20 07:23:34 · answer #1 · answered by rayv 3 · 0 0

68 Fahrenheit To Celsius

2016-10-05 07:38:49 · answer #2 · answered by ? 4 · 0 0

This Site Might Help You.

RE:
What is 68 degrees Fahrenheit in Celsius and Kelvin? How did you get those answers?

2015-08-18 20:40:12 · answer #3 · answered by ? 1 · 0 0

I suspect some of your answers will invoke memorized formulas. But I think it's best to derive what you need because it leads to better understanding of why those memorized formulas work. Let's look at the physics.

In C water boils at 100 degrees and freezes at 0 degrees.
In F water boils at 212 degrees and freezes at 32 degrees.

But boiling and freezing have to happen at the same temperature no matter what units are used. So the units C and F have to be equivalent to give us boiling and freezing at the same temperature even though the units for temperature are different.

OK, then, the difference between boiling and freezing in C is 100-0 = 100 units. For F it's 212 - 32 = 180 units. Assuming the units are linear, this means that 1 unit C = 1.8 unit F. Another way to say this is that for every 1 degree C change, F changes 1.8 degrees.

In math talk, we can write F = 1.8C and, look at this, this looks a lot like y = mx + b, which is the general equation for a straight line. The only thing missing is b, the y intercept when x = 0. What is F when C = 0; it's F = 32 degrees. So, to finish out the F = 1.8C equation, we add the F intercept and have F = 1.8C + 32, which is one of those memorized equations. But now you know where it came from. You can plug in F = 68 degrees and solve for C.

Then, to get K, simply know that water freezing for K ~ 273 degrees. Also know that 1 unit C = 1 unit K; that is, for example, water will boil at 373 degrees K, which is 100 degrees up from the 273 degree freezing temperature like 100 degrees C is up from zero degrees C. The only difference between C and K is that C = 0 at freezing and K = 0 at so-called absolute zero well below water freezing.

As C freezes water at 0 degrees and K freezes water at 273, we need to subtract the 273 from Kelvin to get Centigrade. In math talk, that's C = K - 273. Since you have C when F = 68 degrees, just solve for K = C + 273 and there you have it; yet another "memorized" equation derived.

2007-09-20 07:35:57 · answer #4 · answered by oldprof 7 · 0 0

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This method is simple, accurate and easy to remember. 1/ Take the Fahrenheit temperature and add 40. 2/ Multiply by 5/9 (you can remember this because there are fewer degrees between the freezing and boiling points of water on the Celsius scale) 3/ Subtract 40 = 18.88888888888888889, the correct answer. You can use the same method in the opposite direction except you multiply by 9/5 (going to the larger scale) This works because the two scales share the same point at -40 degrees

2016-04-06 05:38:27 · answer #5 · answered by Anonymous · 0 0

for celsius
9/5 C + 32 = F
9/5 C = 36
C = 20

for kelvin
C + 273 = K
= 293 K

2007-09-20 07:27:11 · answer #6 · answered by SWETA 2 · 0 0

66 degrees Fahrenheit = 18.8888889 degrees Celsius A very good , easy and fast way for conversion online is google. In the google Search box just type "66 degrees fahrenheit in celsius" and click on search and it will give u the results! It can be also used for either kind of conversions like miles to km, km to miles, inches to cm , pounds to kg etc. etc.

2016-03-13 22:08:55 · answer #7 · answered by Anonymous · 0 0

20 C, and 293K

C=5/9 (F-32) and K=C + 273

2007-09-20 07:03:56 · answer #8 · answered by cyswxman 7 · 1 0

20 C
293 K

2007-09-20 07:21:10 · answer #9 · answered by TRACER 3 · 0 0

check MSN Weather, you get an idea.
U can click on both F or C
And there is a site that has the conversion.
If I find it , will get back again.

2007-09-20 07:05:18 · answer #10 · answered by Anonymous · 0 0

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