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i was in regular but got fregin transfered to honors and im not that smart in science and i really need help with these questions soooo if anyone knows the answers i would really appreciate it!!!!!!!!! thanks in advance!!!!!!!!!

A runner traveling with an initial velocity of 2.0 m/s accelerates at a constant rate of 1.9 m/s2 for a time of 3 seconds.

(a) What is his velocity at the end of this time?
m/s
(b) What distance does the runner cover during this process?
m



and


partscoretotalsubmissions1--10/42--10/4----2--A frightened cat, starting from rest, travels a distance of 4.90 m in 3.06 s, accelerating at a constant rate the entire time. What was her acceleration ?
Units?
m/s2
m
m2/s2
ms
m/s

and
A bus is accelerating at a rate of 0.340 m/s2. You are standing on the sidewalk as bus drives by. Exactly 3.31 s later it is travelling at 3.44 m/s. What was the velocity of the bus at the instant it passed you?
Units?
m
ms
m/s2
m/s
m2/s2
plz help!!

2007-09-20 05:33:28 · 3 answers · asked by Anonymous in Science & Mathematics Physics

3 answers

A runner traveling with an initial velocity of 2.0 m/s accelerates at a constant rate of 1.9 m/s2 for a time of 3 seconds.

(a) What is his velocity at the end of this time?
m/s
(b) What distance does the runner cover during this process?
m

u = 2.0
a = 1.9
t = 3
v = ?

v = u + at

v^2 = u^2 + 2as


ms^-2


m/s

2007-09-20 05:43:27 · answer #1 · answered by   4 · 0 0

Here's the first one:

v = v0 + at = 2 m/s + 1.9 m/s^2*3 sec =7.7 m/s

Second one:

x = x0 + v0*t +1/2a*t^2 =0 + 0 + 1/2a(3.06 s)^2 = 4.9 m

v0 = 0 since cat was at rest.

a = 9.8m/(3.06s)^2 = 1.05 m/s^2

Third one:

v = v0 +at ---> want to find v0

v0 = v - at =3.44 m/s - 0.34 m/s^2*3.31 sec = 2.32 m/s

2007-09-20 05:49:12 · answer #2 · answered by nyphdinmd 7 · 0 0

vertical action s =ut +0.5 at^2 0 = 1770 sin 40 seven.a million t - 0.5 * 9.8 * t^2 0 = t ( 1770 sin 40 seven.a million - 0.5 * 9.8 * t ) t=0 or 1770 sin 40 seven.a million - 0.5 * 9.8 * t =0 t = 1770 sin 40 seven.a million / 0.5 * 9.8 s answer

2016-10-05 01:48:39 · answer #3 · answered by ? 4 · 0 0

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