log(base a) x + log(base a) x^2 + log(base a) x^3 + log(base a) x^4 = 5
2007-09-20 04:48:39 · 6 answers · asked by keshema2003 2 in Science & Mathematics ➔ Mathematics
well what rules do you know involving logarithms? one is that :-
log(A) + log(B) + log(C) + log(D) = log(ABCD)
for some base and positive values of A,B,C,D
how does this then help you?
well, looking at what you have and using the above rule, we can say :-
log(x * x^2 * x^3 * x^4) = 5
log(x^10) = 5
(where 'log' here means 'log base a' )
now, theres another rule that says :-
log(x^n) = nlog(x)
so, using this rule then:-
log(x^10) = 10log(x) = 5
so, log(x) = 1/2
x = a^1/2
2007-09-20 05:00:37 · answer #1 · answered by Jeremy W 3 · 1⤊ 0⤋
property of logarithms:
log(base a)x + log(base a)y = log(base a) (xy)
thus, simplifying the given:
log(base a) x^10 = 5
thus,
10 log(base a)x =5
and
log(base a)x=0.5
thus
a^0.5 = x
or
sqrt(a) = x
2007-09-20 05:03:03 · answer #2 · answered by nj 2 · 1⤊ 0⤋
log(base a) x+x>2+X>3+x>4= 5
log(base a) x+x-x-x=->2->3->4=5
=>Spagetti+bologness= Italian food
=> sorry i can't help I did try though
2007-09-20 05:29:04 · answer #3 · answered by Max Skinner 3 · 0⤊ 1⤋
Log(a)x + 2log(a)x + 3log(a)x + 4log(a)x = 5
10log(a)x = 5
log(a)x = 5/10 = 0.5
log(a)x = 1/2
x = a^1/2 = sq rt a
2007-09-20 05:06:11 · answer #4 · answered by lenpol7 7 · 1⤊ 0⤋
welding with butter
2007-09-20 04:51:18 · answer #5 · answered by lyndon n 3 · 1⤊ 0⤋
x = a^0.5
2007-09-20 04:59:40 · answer #6 · answered by Superdude 5 · 1⤊ 0⤋