Well, let's see, if all the animals are anatomically normal the dogs and cats have 4 legs each, so:
(2+3)x4 = 5x4 = 20
Then 9 chickens with 2 legs each is:
9x2 = 18
20+18 = 38, so false.
2007-09-20 04:30:11
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answer #1
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answered by jurydoc 7
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If chickens only have 2 legs
and dogs only have 4 legs
and cats only have 4 legs.
Using logical deduction we simply multiply the number of legs by the number of animals.
9 X 2 = 18 legs
+
2 x 4 = 8 legs
+
3 x 4 = 12 legs
TOTAL = 18+12+8 = 38 Legs.
HOWEVER
You weren't clear as to whether or not any of the animals are deformed. It's very possible (however unlikely) that some of them have too many legs due to some freak accident that has left them deformed
2007-09-20 04:36:23
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answer #2
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answered by Rob 3
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False unless it is a trick question. They would have 38 legs.
2007-09-20 04:31:18
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answer #3
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answered by Anonymous
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Unless there has been some mutation or this is one heck of a trick question it has to be 38
2007-09-20 04:35:39
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answer #4
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answered by PROBLEM 7
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9x2 & 2x4 & 4x3 = 38 legs.
2007-09-20 04:31:00
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answer #5
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answered by MDJ 1
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false...i only count 38
2007-09-20 04:33:29
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answer #6
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answered by cecee 4
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Only if one of them is on crutches.
2007-09-20 04:34:04
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answer #7
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answered by Anonymous
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f***kin retard thers 38 legs
2007-09-20 04:33:27
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answer #8
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answered by Anonymous
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Gosh..... are you kidding me? !
2007-09-20 04:29:20
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answer #9
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answered by Anonymous
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