W=F x S....i've a problem regarding this........?

Question

If W= F x S
then If we keep the work done constant..then..
Force should be inversely propotional to the displacement produced.....
but its ain't seen in the real lyf...
more is the force the more is the displacement and vice -versa.....

Answer 1

The more the force the more the displacement applies to pushing against something elastic (e.g., a spring). In that case f increases with s and work done is the average force, which = final force/2, times s. In formula form,
w = f(ave)s = f(final)s/2
And since f(final) is proportional to s, w is proportional to f(final)^2 or to s^2.
Using k to designate spring stiffness,
f(final) = ks
w = f(final)s/2 = ks^2/2 = f(final)^2/(2k)
When elasticity is not involved (e.g., rolling a cart uphill), if speed is constant then f is constant and w = fs. In this case the inverse relation between f and s does apply (contrary to the 1st answer).

Answer 2

If we keep the work done constant..
then how far the object goes will depend on the force, so the displacement depends on the force.

not Force should be inversely propotional to the displacement produced.

Answer 3

What the relationship says is that to do a specific amount of work, if you push twice as hard, you only have to go half as far. If you can only push half as hard, you will have to go twice as far. You can rig up pulleys so that you can lift a 1000 lb object with only 100 lb of force. But for every foot you want to lift it, you will have to pull the rope 10 feet. It's a tradeoff.

And that example is from real lyf. :)

Answer 4

You are very correct. Force is inversely proportional to displacement., provided "work is kept constant"

Answer 5

you're right