Been a while since I've used this stuff, someone refresh my memory please.
2x+3y=12
-2x
3y=12-2x
-3
y=12/3-2x
y=4-2/3x ?
I know that is wrong lol.. like i said been a while since i used this stuff. Thanks in advance!
2007-09-19 20:42:05 · 9 answers · asked by tentoesdown 2 in Science & Mathematics ➔ Mathematics
Looks like you're on the right track.
Original Problem
2x + 3y = 12
Subtract 2x from each side to isolate y
2x-2x + 3y = 12 - 2x
3y = 12 - 2x
Multiply by 1/3 to remove the coefficient
(1/3)3y = (1/3)(12-2x)
y = (1/3)(12-2x)
Simply with the distributive property (a)(b+c) = ab + bc
y = (12/3) - (2x)(1/3)
y = 4 - (2/3)(x)
Rewrite in usual form
y = (-2/3)x + 4
So, it seems that (other than the optional rewriting for clarity), you were correct.
2007-09-19 20:52:55 · answer #1 · answered by hogan.enterprises 5 · 1⤊ 1⤋
2x + 3y = 12
3y = 12 - 2x
y = 4 - 2/3x
2007-09-19 21:08:07 · answer #2 · answered by gab BB 6 · 0⤊ 1⤋
2x + 3y = 12
3y = 12 - 2x Subtract 2x from both sides.
y = 4 - 2/3x Divide 3 on both sides.
You're correct!
But if you want a numerical value for y, you'll need another equation involving x and y. 2 variables = 2 equations, 3 variables = 3 equations.
2007-09-19 20:52:10 · answer #3 · answered by AlexD 2 · 0⤊ 1⤋
Bring 'y' to one side of the original equation.
3y=12-2x
y=3(12-2x)
y=36-6x -------(1)
Convert 'x' into a 'y' equation
2x=12-3y
x=2(12-3y)
x=24-6y -------(2)
Substitute (2) in (1)
y=36-6x
y=36-6(24-6y)
y=36-144+36y
y=-108+36y
-36y+y=-108
-35y=-108
y=108/35
y=3.08571428571
2007-09-19 21:08:02 · answer #4 · answered by mYsTiC 1 · 0⤊ 0⤋
3y = - 2x + 12
y = (- 2 / 3) x + 4
2007-09-20 23:46:38 · answer #5 · answered by Como 7 · 1⤊ 0⤋
2x + 3y = 12
3y = -2x + 12
y = -(2/3)x + 4
2007-09-19 21:10:39 · answer #6 · answered by The Glorious S.O.B. 7 · 0⤊ 1⤋
that's correct. Check your answer by substitution. Say Y=2 & X=3.
2007-09-19 21:01:39 · answer #7 · answered by Rudey 1 · 1⤊ 0⤋
2x + 3y = 12
3y = 12 -2x
3y = 10
y = 10/3
y = 3.333
I think that's it. I'm still studying algebra. I hope that helps.
You're welcome! ^_^
2007-09-19 20:51:48 · answer #8 · answered by freakgurl_anime lover 1 · 0⤊ 1⤋
dude
get real
u cant solve the problem
u give 2 variables and one relation
aint gonna work
helloooo..........
u require n relations to solve for n variables
2007-09-19 20:50:15 · answer #9 · answered by SAT 2 · 1⤊ 2⤋