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2 answers

Molarity = No. of Moles of Solute / Vol. of solution in litres

let us assume 1lt of this solution,and let number of moles be x.

0.5=x/1,

x=0.5

Therefore no. of moles are 0.5.

now Normality for acids = No. moles of acid / (Vol. of sol in lts * Basicity)

as H2SO4 has 2 replacable hydrogen ions therefore basicity is 2.

Normality= 0.5/(1*2)

Normality= 0.25

ans: Normality of 0.5 M sulphuric acid is 0.25 N.

PS: No need to write (what is the normality of 0.5 molar sulphuric acid conc? ) conc in your question.

2007-09-19 20:44:27 · answer #1 · answered by Anonymous · 0 3

Sulfuric acid is H2SO4. One mole of the acid contains two moles of H, so the normality is 2 x molarity. 0.5 M sulfuric acid is 1.0 N

2007-09-19 20:34:21 · answer #2 · answered by gp4rts 7 · 1 0

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