Help with simplifying!!!?

Question

Ok I understand how to simplify in class with these easy examples we get but I get hom and I get

x^2 x^6
______
x^3

Now when we get these x's I get confused. Any help and explanation is appreciated. Also if you know any good sites that would be helpfull. Thanks

Answer 1

Basically you just need to remember the properties of exponents. They should be located in your math book. For this particular problem, you should solve it in this way.

Step 1: Simplify numerator to x^8. (When you multiply exponents with the same base, such as x^2 * x^6, you can add the exponents together)

Step 2: Simplify fraction to x^5. (When you divide exponents with the same base, such as x^8/x^3, you can subtract the exponent of the denominator from the exponent of the numerator.

Answer: x^5

Answer 2

if there is x's on as the coefficinent ur ok to add the powers if they are multiplied together

x^2*x^6= x^(2+6)
x^8

then when x's are the coefficient and u r dividing its a matter of subtracting the powers

x^8 / x^3= x^(8 - 3)
= x^5

Answer 3

x^2*x^3=x^5

Answer 4

The answer is x^5 :

(x^2*x^6)/x^3 =
(x^(2+6))/x^3=
x^8/x^ 3=
x^(8-3)=x^5

Answer 5

x^(2+6-3)
=x^5

Answer 6

thing to remember is if the bases are the same you can add the exponents and when you divide you then subtract the exponents
x^8/x^3

= x^5

Answer 7

x^2 x^6
______ work on top. x^n * x^m = x^(n+m), so
x^3


x^8
------- , now, x^n/x^m = x^(n-m), or
x^3

x^(8-3) = x^5. done.

Answer 8

x^8 / x^3 = x^5

Rules
Multiply-->Add indices-->(x^a)(x^b) = x^(a + b)
Divide-->Subtract indices-->x^a / x^b = x^(a - b)