how do i differentiate this expression...
just the answer would do as well... to tell you the truth...
(sinx)^7
2007-09-19 18:15:23 · 8 answers · asked by vitania 2 in Science & Mathematics ➔ Mathematics
Let y = (sin x) ^ 7
let u = sin x
du/dx = cos x
y = u ^ 7
dy/du = 7 u ^ 6
dy/dx = (dy / du) (du / dx)
dy/dx = 7 u ^ 6 cos x
dy/dx = 7 ( sin x )^6 (cos x)
2007-09-20 01:27:40 · answer #1 · answered by Como 7 · 2⤊ 0⤋
7(sinx)^6+cosx
I know the by using the differentiation rules
2007-09-19 18:27:32 · answer #2 · answered by Rayan Ghazi Ahmed 4 · 0⤊ 2⤋
= 7 * (sinx)^6 * cos x dx
2007-09-19 18:20:53 · answer #3 · answered by Seto 2 · 0⤊ 0⤋
7(sinx)^6 ... i think its been a while
2007-09-19 18:18:31 · answer #4 · answered by Danny G 2 · 0⤊ 1⤋
y=(sinx)^7
dy/dx = 7*cosx*(sinx)^6
2007-09-19 18:25:59 · answer #5 · answered by Anonymous · 0⤊ 0⤋
f(x)=(sinx)^7
f'(x)=7*(sinx)^6 * cos x
2007-09-19 18:21:27 · answer #6 · answered by ptolemy862000 4 · 0⤊ 0⤋
y = (sin x)^7
Let u = sin x
du/dx = cos x
y = u^7
dy/du = 7u^6
= 7(sin x)^6
dy/dx = dy/du * du/dx
= 7[(sin x)^6] * cos x
= 7(sin^6 x) (cos x)
2007-09-19 18:20:19 · answer #7 · answered by gudspeling 7 · 0⤊ 0⤋
7sinx^6cosx
2007-09-19 18:23:43 · answer #8 · answered by nan 1 · 0⤊ 0⤋