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solve the system of xy = 1, x + y = a by using the identity:

((x -y) / 2)^2 = ((x + y) / 2)^2 - xy

??????? I have no idea ??????????

2007-09-19 18:00:57 · 7 answers · asked by busy bee 2 in Science & Mathematics Mathematics

7 answers

Do you remember the first two identities that we were taught in algebra classes?
These are
(x+y)^2=x^2+2xy+y^2 and (x-y)^2=x^2-2xy+y^2
we were also taught that
(x-y)^2=(x+y)^2-4xy
dividing both sides by 4,we get
(x-y)^2/4=(x+y)^2/4-4xy/4
or,{(x-y/2)}^2={(x+y/2}^2-xy
Now if you have the values of x+y and xy,input them in the above formula toget
{(x-y)/2}^2=(a/2)^2-1
or (x-y)/2}^2=a^2/4 -1=(a^2-4)/4
or,(x-y)/2= sqrt(a^2-4)/2
or,x-y=sqrt(a^2-4)
Now you have two equations
x+y=a and x-y =sqrt(a^2-4)
solving we get
x={a+sqrt(a^2-4)}/2
y={a-sqrt(a^2-4)}/2

2007-09-19 18:25:19 · answer #1 · answered by alpha 7 · 1 0

Let us simplify the system first
((x-y)^2/2^2) = ((x+y)^2)/2^2) - xy
(x-y)(x-y)/4 = (x+y)(x+y)/4 -xy
multiply both sides with 4 we get
(x-y)(x-y)=(x+y)(x+y)-4xy
x^2-xy-xy+y^2=(x+y)(x+y)-4xy
Now use given information(xy=1,x+y=a) we get
x^2-1-1+y^2=(a)(a)-4
x^2 + y^2=a^2 - 2

2007-09-19 18:23:17 · answer #2 · answered by Rayan Ghazi Ahmed 4 · 0 0

Not difficult: 3x + 4y = -16, 3x + 11 = y... or; 3x - y = -11 Subtract out the second equation from the first. 5y = -5 y = -1 And now solve for x: 3x + 4y = -16, 3x + 11 = y 3x + (-4) = -16, 3x + 11 = (-1) 3x = -12, 3x = -12 x = -4, x = -4 y = -1 and x = -4 No mistaking it from the above. It's an ironclad proof!

2016-05-19 00:20:52 · answer #3 · answered by ? 3 · 0 0

yes i agree with the first answer, other wise ur just becoming a parrot in the sense that u dnt understand how to do it, but u just do them through memory... if u get that. i have no idea how 2 do that either lol, but i sugest u start off doing easier versions of this, then build up, practice makes perfect!!

2007-09-19 18:06:41 · answer #4 · answered by Anonymous · 0 0

((x -y) / 2)^2 = ((x + y) / 2)^2 - xy
((x -y) / 2)^2 = (a/2)^2 -1 =a^2/4-1 = (a2-4)/4
(x-y)/2 = sqrt(a^2-4)/2
x-y = sqrt(a^2-4)
x+y = a
2x = a+sqrt(a^2-4)
x = [a+sqrt(a^2-4)]/2
y = a- [a+sqrt(a^2-4)]/2

2007-09-19 18:23:17 · answer #5 · answered by ironduke8159 7 · 0 0

figure it out. Having someone else do it for you is not the answer. What are you learning if you dond't figure it out?

2007-09-19 18:04:00 · answer #6 · answered by Judy 6 · 0 0

DO YOUR OWN HOMEWORK!!

2007-09-19 18:07:10 · answer #7 · answered by BobRoberts01 5 · 0 0

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