The Slope of a line is -2 and it passes through the point (1,-5).?

Question

write the equation of the line in slope- intercept form

Answer 1

the point slope form is this; y - y1 = m (x - x1)
where y1= -5, x1= 1, m= -2
substitute those values in the slope point form
y -(-5) = -2(x - 1)
y + 5 = -2x + 2
y +2x = -3

then reduce this to the slope intercept form like you wanted
To reduce the equation to the slope intercept form, we solve the equation for y terms of x. hence,
y = -2x - 3

thats the answer!

Answer 2

Line equation in the slope-intercept form is written as y = mx + b (where m and b are numerals, and x and y are variables) in which m is the slope and b is the y-intercept.

m = -2
y = mx + b
y = -2x + b

We know that the line passes through the point (1,-5)
Hence,
-5 = -2(1) + b
-5 + 2 = b
b = -3
So the equation of the line is:
y = -2x - 3 or y = -(2x + 3) or y + 2x = -3

Answer 3

the standard form of slope intercept equation is

y = mx + c , where m = slope and c is the y intercept

here slope m = -2

so the equation of required line is

y = -2x + c

as it passes through the coordinates (1, -5), substitute

x = 1 and y =- 5 in the equation

-5 = -2(1) + c

-5 = -2 + c

c = -5 + 2 = -3

So the equation of required line is

y = -2x - 3

y + 2x + 3 = 0

Answer 4

If m is the slope and b is the y-intercept, y=mx+b is the line, so y=-2x+b. Solve for b:

-5=-2(1)+b
-3=b

y=-2x-3

Answer 5

y=mx+b
m(slop)=-2
point coordinates(x,y) point (1,-5) then x=1 and y= -5
the equation of line well be
y=-2x (if the line passes the origin point(0,0)
OR y=2x+b (if the line does not pass though the origin point)

Answer 6

y + 5 = ( - 2 ) (x - 1)
y + 5 = ( - 2 ) x + 2
y = ( - 2 ) x - 3

Answer 7

y= - 2x-3

Answer 8

y=mx+b