What is this balls speed when it leaves the table and how long is it in the air?

Question

A small ball rolls horizontally off the edge of a tabletop
that is 1.20m high. It strikes the floor at a point 1.52m horizontally from the table edge. (a) How long is the ball in the air? (b) What is its speed at the instant it leaves the table? Show and explain your work. Thanks :)

Answer 1

The equations for this are
y(t)=1.2-.5*g*t^2
at the moment the ball strikes the floor, y(t)=0

It only has horizontal velocity when it leaves the table, so
x(t)=v0*t

at the moment the ball strikes the floor
1.52=v0*t
and
0=1.2-.5*g*t^2
t=sqrt(2.4/g)

use 9.81 for g
t=0.5 seconds
and v0=3.04 m/s

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