Calculas Question... Please help.?

1 ⤊

Calculas Question... Please help.?

I am currently stuck on this question and I dont know how to start it.

[ (3u+4)(2u-2)^3 ] / [ (u-1)^2 ]

Additional Details
This is as u approaches 1 sorry

2007-09-19 15:45:15 · 1 answers · asked by Pngo 1 in Science & Mathematics ➔ Mathematics

1 answers

Find the limit.

Limit u→1 { [(3u + 4)(2u - 2)³] / (u - 1)² }

= Limit u→1 { [(3u + 4)8(u - 1)³] / (u - 1)² }

= Limit u→1 { [8(3u + 4)(u - 1)] = 0

2007-09-19 15:57:19 · answer #1 · answered by Northstar 7 · 1⤊ 0⤋