Hard physics question please help i can't figure it out?

Question

An electron of mass 9.11 10-31 kg has an initial speed of 5.00 105 m/s. It travels in a straight line, and its speed increases to 6.00 105 m/s in a distance of 9.00 cm.
(a) Assuming its acceleration is constant, determine the force exerted on the electron.
N (in the direction of motion)

if tried but i can't figure the time and if i get the time i can find the acceleration and the force,please help

Answer 1

So you have an initial speed, and a final speed, and you know the distance traveled. So there is a formula that is has a Velocity 1 and a Velocity 2, and has distance and acceleration.. check the text book, that is the formula that will get you the acceleration.

Once you have the acceleration: F=ma and you know the mass, and you just figured out the acceleration... your set.

You just need to search the chapter for the formula for change in velocity...

-luck

Answer 2

Find acceleration from:

x = (v^2 - v0^2)/(2a) ---> a = (v^2 - v0^2)/(2x)

a =[(6x10^5)^2 - (5x10^5)^2]/(2*0.09)

Then F = ma

Answer 3

What you know: v0, v, d
What you want: a
Use: a = (v² - v0²) / (2d)
a = [(6x10^5 m/s)² - (5x10^5 m/s)²] / (2·0.09 m)
= 6.11x10^11 m/s²

F = m·a = (9.11x10^-31 kg)(6.11x10^11 m/s²)
= 5.57x10^-19 N

Answer 4

what the ************ below me said