2007-09-19 14:46:53 · 10 answers · asked by slamdunker3 1 in Science & Mathematics ➔ Mathematics
If n is the first of these even integers, then the next even integer up from that is n+2. So the sum is n + (n+2). Set this equal to 90 and solve for n.
n + (n+2) = 90
2n + 2 = 90
2n = 88
n = 44, and that means the other number is n+2 or 46.
2007-09-19 14:50:58 · answer #1 · answered by Anonymous · 2⤊ 1⤋
An even number is x = 2k
2 consecutive even numbers are 2k and 2k+2
the sum is 90, then
2k + 2k + 2 = 90
4k = 88
k = 88/4 = 22
So the two numbers are
x1 = 44 and x2 = 46
2007-09-19 21:53:20 · answer #2 · answered by Christine P 5 · 1⤊ 1⤋
46 + 44
2007-09-19 21:56:15 · answer #3 · answered by Anonymous · 0⤊ 2⤋
n is first even
(n+2) is the next one consecutively SO
n + (n+2) = 90
2n + 2 = 90
2n = 88
n=44
so the answers are 44 and 46
2007-09-19 21:55:28 · answer #4 · answered by RickSus R 5 · 1⤊ 1⤋
44 and 46
2007-09-19 21:56:35 · answer #5 · answered by julia S 2 · 0⤊ 2⤋
44 and 46
2007-09-19 21:51:26 · answer #6 · answered by mazdamandan 4 · 0⤊ 2⤋
44 and 46?
2007-09-19 21:51:16 · answer #7 · answered by David N 2 · 0⤊ 2⤋
2n + (2n + 2) = 90
4n = 88
n = 22
Integers are 44 and 46
2007-09-22 11:12:10 · answer #8 · answered by Como 7 · 2⤊ 1⤋
There are no consecutive even integers
2007-09-19 21:53:29 · answer #9 · answered by Anonymous · 1⤊ 4⤋
forty-four & forty-six
2007-09-19 21:57:22 · answer #10 · answered by The Glorious S.O.B. 7 · 1⤊ 2⤋