if a man who is homozygous for normal vision marries a woman wo is heterozygous for farsightedness, what porti

Answer 1

What portion of their offspring would we expect to have normal vision? NN x Nn = 1NN: 1Nn If normal is dominant, then the answer is 100% of the children would have normal vision. If farsightedness is dominant, then the answer is 0% of the children would have normal vision.

Answer 2

The Punnett square cross on this is NN x Nn.
You get 2 NN and 2 Nn children from this cross.

If Normal vision is only exhibited when homozygous, 2 children have normal vision (the 2 NN's) -- and the other two are farsighted (the 2 Nn's).

If the Normal vision gene is dominant, all children have normal vision.

Answer 3

You didn't finish your question. But it would seem the children would be normal vision providing other factors do not come in to play.