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#1 Specify what ions are present in solution upon dissolving each of the following in water:
a) zinc chloride
b) nitric acid
c) ammonium sulfate
d) calcium hydroxide


#2 Formic acid, HCHO2, is a weak electrolyte. What solute particles are present in an aqueous solution of this compound? Write the chemical equation for the ionization of formic acid.

2007-09-19 14:29:38 · 3 answers · asked by joey 1 in Science & Mathematics Chemistry

3 answers

#1
a) Zn2+ 2Cl-
b)H+ NO3-
c) 2NH4+ SO42-
d) doesn't dissolve

#2
H+ CHO2- HCHO2 are present
HCHO2 -->H+ + CHO2-

2007-09-19 14:37:03 · answer #1 · answered by She-Who-Must-Not-Be-Named 3 · 0 0

a) Zinc chloride has the formula ZnCl2. When it dissolves, it will form zinc ions (Zn2+) and 2 chloride ions (Cl-)
b) HNO3 is a strong acid. It will transfer its hydrogen onto water molecules forming hydronium ions (H3O+) and nitrate ions (NO3^-)
c) you will have ammonium ions (NH4+) and sulfate ions (SO4^2-). Depending on how picky you need to be, some of the ammonium ions will act as a weak acid and will form a small amount of hydronium ion and ammonia (NH3).
d) You'll have calcium ions (Ca2+) and hydroxide ions (OH-)

Since formic acid is a weak acid, a small number of the molecules will transfer their hydrogen to water forming hydronium ions and formate ions. The equation would be:

HCHO2 + H2O --> H3O+ + CHO2-

2007-09-19 21:43:47 · answer #2 · answered by hcbiochem 7 · 0 1

#1)a) Zn^2+ and CI^- ions
b) H3O^+,NO3^-
c)NH4^+,SO4^2-
d)Ca^2+,OH^-

2)PARTICLES-H3O^+ , COOH^-
IONIZATION:HCOOH=H^(+) + COOH^-

2007-09-19 21:38:06 · answer #3 · answered by Dr. Eddie 6 · 0 1

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