You are presented with three white solids, A, B and C, which are glucose (a sugar substance), NaOH,
and AgBr. Solid A dissolves in water to form a conducting solution. B is not soluble in water. C dissolves in water to form a nonconducting solution. Identify A, B, and C.
2007-09-19 13:11:53 · 2 answers · asked by joey 1 in Science & Mathematics ➔ Chemistry
Glucose dissovles in water, but is not an ionic compound. Therefore, glucose will not conduct electricity when dissolved. Glucose is Solid C.
NaOH is an ionic solid. This makes it dissolve in water and will conduct electricty very well. NaOH is Solid A.
AgBr is insoluable in water. We can check the solubility rules in the link below to learn this. AgBr is Solid B.
2007-09-19 13:16:13 · answer #1 · answered by lhvinny 7 · 0⤊ 0⤋
NaOh dissolves in water and is conductive, Na+ ,0H- ions
glucose, sugar is soluble and non-conductive (non-ionic)
AgBr is insoluble in water
2007-09-19 13:17:25 · answer #2 · answered by 2hard4me 3 · 1⤊ 0⤋