A block of mass m is released from rest at a height R above a horizontal surface. The acceleration due to gravity is g. The block slides along the inside of a frictionless circular hoop of radius R.
Which one of the following expressions gives the speed of the mass at the bottom of the hoop?
a. zero m/s^2
b. v^2 = 2gR
c. v^2=(g^2)/R
d. v = mgR
e. v = mg/2R
2007-09-19 13:10:08 · 2 answers · asked by lil_britt0737 1 in Science & Mathematics ➔ Physics
it is b
Potential energy (Pe) on top equal to kinetic energy (Ke) at the bottom.
Pe= Ke
mgR=0.5 mV^2
so
V^2= 2 g R
2007-09-22 08:10:25 · answer #1 · answered by Edward 7 · 0⤊ 0⤋
you like 2 equations = d = a million/2*a*t^2. you realize, a, gravitational acceleration. resolve for t - the quantity of time the toy automobile fake. Now, use that element to compute v=at Assuming you held it nonetheless in the past liberating it, the linked fee it has while it hits the ramp is the replace.
2016-10-09 12:10:35 · answer #2 · answered by ? 4 · 0⤊ 0⤋