h(x) = 1/ x^2 -4x?

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please explain

2007-09-19 13:02:54 · 2 answers · asked by eric j 1 in Science & Mathematics ➔ Mathematics

2 answers

So h is some function of x. The only thing to explain is whether you mean (1/x^2) - 4x or 1 / (x^2 - 4x).

2007-09-19 13:08:02 · answer #1 · answered by Anonymous · 0⤊ 0⤋

Do you mean 1/(x^2-4x) or (1/x^2) -4x? Please always use parentheses to make your meaning clear.

If it is the 1st case, the h(x) has vertical asymptotes at x=0 and at x=4. It has a horizotal asymptote at y=0.

The function has no real roots.

In the 2nd case the function has a root at approx .625. It has a vertical asymptote at x =0.

I'm not sure what explanation you are looking for.

2007-09-19 20:25:53 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋