How do you start of these math problems??? quadratic equations??

Question

i just need the beginning...the rest i can probably manage.
express in the simplest radical form to the nearest hundredth:

x squared + 3 = 7x how do i fix it so it quals to 0 its really easy but i forgot lol.



2x squared + 1 = 4x
this one also. how/?

Answer 1

x^2 + 3 = 7x, subtract 7x
x^2 - 7x + 3 = 0


2x^2 + 1 = 4x, subtract 4x
2x^2 - 4x + 1 = 0


then use the quadratic equation to find x

Answer 2

Ummmm.... You just want to 'fix it to equal 0'?

x^2 + 3 = 7x
x^2 -7x + 3 = 0

2x^2 + 1 = 4x
2x^2 - 4x + 1 = 0

Answer 3

x^2 -7x +3 = 0

2x^2-4x+1 = 0

You can move things from one side of the = signn to the other if you change its sign.

Answer 4

i do now no longer evaluate myself a math whiz, yet i think of of i'm able to try this for the duration of my head. Subtract +7 from the two aspects hassle-unfastened adequate! keep in mind that provides you with you with (y-7) on the left area... .Divide it via potential of (x-30)^2 that leaves (y-7) / (x-30)^2 = a (in terms of x & y)

Answer 5

Get them into the form of ax^2 + bx + c = 0, then either factor it into two terms, or use completing the square, or the quadratic formula.

These pages explain more:
http://mathforum.org/library/drmath/view/60700.html
http://mathforum.org/library/drmath/view/53023.html
http://mathforum.org/library/drmath/view/52992.html