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While riding on an elevator descending with a constant speed of 2.4 m/s, you accidentally drop a book from under your arm.
(a) How long does it take for the book to reach the elevator floor, 1.2 m below your arm?
s
(b) What is the book's speed relative to you when it hits the elevator floor?
m/s

2007-09-19 11:38:20 · 1 answers · asked by jkopinto 1 in Science & Mathematics Physics

1 answers

The acceleration of the book will be g. So inside the elevator at constant speed it is if you are standing on the ground and drop the book.

so
1.2=.5*g*t^2
solve for t

with t
v=g*t downward

j

2007-09-19 11:50:41 · answer #1 · answered by odu83 7 · 0 0

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