The best leaper in the animal kingdom is the puma, which can jump to a height of 11.1 ft when leaving the grou

Question

ground at an angle of 49 degrees With what speed, in SI units, must the animal leave the ground to reach that height?
m/s

Answer 1

the max height is achieved when the y component of velocity is zero, and halfway through the total flight

y(t)=11.1=v0*sin(49)t-16*t^2
and
v(t)=0=v0*sin(49)-32*t
so v0*sin(49)=32*t
solve for t
11.1=16*t^2
t=sqrt(11.1/16)
0.8 seconds
now compute the v0
v0=32*.08/sin(49)
3.39 ft/sec

convert to m/s

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