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cscA= sqrt(5)/2

Draw a right triangle withe legs = 1 and 2. Then hypotenuse must be sqrt(5) . CotA = 1/2, so cscA = sqrt(5)/2

2007-09-19 11:40:09 · answer #1 · answered by ironduke8159 7 · 0 0

cotA = 1/2

cot^2 A = 1/4

cos^2 A/sin^2 A = 1/4

(1- sin^2 A)/sin^2 A = 1/4
1/sin^2 A - 1 = 1/4
1/sin^2 A = 1 + 1/4 = 5/4
csc^2 A = 5/4
csc A = sqrt(5)/ 2

2007-09-19 18:41:41 · answer #2 · answered by mohanrao d 7 · 0 0

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