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2007-09-19 10:38:10 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

i^10= (i^2 )^{- 5)} = (-1) ^{-5)} = 1 / (-1)^5 = 1/ (-1) = - 1

2007-09-21 06:33:51 · answer #1 · answered by Anonymous · 1 0

i^-10 =
(i^2)^-5 =
(-1)^-5 =
-1

2007-09-19 10:41:36 · answer #2 · answered by Anonymous · 1 0

= [ i^( 2) ]^(- 5)
= (-1) ^(-5)
= 1 / (-1)^5
= 1/ (-1)
= - 1

2007-09-20 10:50:43 · answer #3 · answered by Como 7 · 2 0

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