help please! algebra 2 absolute value inequailty problem!?

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l x/3 + 4 l >7

2007-09-19 08:39:25 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

|x/3 +4| >7
|x + 12/3|>7
(x+ 12)/ 3 >7
x+12 > 7 x 3
x +12 > 21
x > 21 - 12
x> 9

2007-09-19 08:45:35 · answer #1 · answered by Varshita 3 · 0⤊ 0⤋

l x/3 + 4 l >7
-7 >x/3 +4 >7 Rewrite
-21 > x+12 > 21 Multiply by 3
-33>x > 9 Subtract 12

2007-09-19 08:47:42 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋

x/3+4>7
x/3+4-4>7-4
x/3>3
3*x/3>3*3
x>9

2007-09-19 08:47:51 · answer #3 · answered by Zero 4 · 0⤊ 0⤋

Already solved!

x > 9 or x < -33

2007-09-19 08:44:33 · answer #4 · answered by Dave 6 · 0⤊ 0⤋