I need to find the nth term of the pattern : 2, 4, 8, 16, 32.?

Question

I know that you multiply the term by 2 but i dont know how to make that work for the nth term equation, I tried Ax^2 + Bx + c and it didnt work...so if anyone can help me i would appreciate it! Thanks!

Thanks everyone for the answers! helped tons!

Answer 1

Term ""1""2""3""4""5"""6"""n
Value""2""4""6""8""10"12"2n

nth term is 2n

Answer 2

Since each term is multiplied by 2, and the first term is 2,
the nth term is just 2 multiplied by itself n times.

This is simply 2^n or
.... 2 * 2 * 2 * 2 * 2 * 2 * 2 .....
n times.

Your SECOND order (quadratic) equation Ax^2 + Bx +C
is good only for the SECOND term, with x=2
(B and C are set to zero and A is 1).
For the THIRD term, you'd need x^3 (not x^2),
x^4 for the FOURTH term, and so on.
But why bother with polynomials?

All you need for the nth term is 2 raised to the n power.

The first ten terms are:
.... 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024
(Notice how the tenth term is a little more than one thousand.
The twentieth term is a bit more than one million!)
The thirtieth is a somewhat more than a billion!)

The next ten terms (11th to 20th) are:
2048
4096
8192
16384
32768
65536
131072
262144
524288
1048576

Answer 3

Nth term of the partern is= 4/2=8/4=32/16, which means that the Nth term=2.

Answer 4

This is a Geometric Progression.
Consider the first term to be a = 2 and the successive terms to be multiplied by the factor r = 2.

Then formula for the nth term,

Tn = a * r^(n-1)
Tn = 2 * 2^(n-1)
Tn = 2^n.

Hope this helps.

Answer 5

It is a Geometric Progression with first term a=2 and ratio r=2
nth term is given as a*r^(n-1)
Therefore, 2*2^(n-1)
Which is 2^n

Answer 6

It's an exponential. The nth term is 2^n.

Answer 7

2^n where n is a postive integer

Answer 8

x=2^n, or n = log2(x)