2007-09-19 06:42:26 · 10 answers · asked by Karen K 1 in Science & Mathematics ➔ Mathematics
(sqrt3)(-2sqrt3)
= -2*3
= -6
2007-09-19 06:49:29 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
-6 root 3
2007-09-20 16:03:23 · answer #2 · answered by keshema2003 2 · 0⤊ 1⤋
root 3 x root 3 = 3
3 x -2 = -6
^_^
2007-09-19 17:29:40 · answer #3 · answered by pazuzu_futurama 2 · 0⤊ 1⤋
(â3)(-2)(â3) = (-2) â3 â3 = (- 2) x 3 = - 6
2007-09-19 14:40:42 · answer #4 · answered by Como 7 · 2⤊ 0⤋
(â3)(-2â3)
First: combine the numbers in the radical signs.
-2â(3*3)
SEc: when a number is repeated twice, take it out & combine it with the outer term (in this case).
-2(3) = -6
2007-09-19 13:55:56 · answer #5 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
-6 root 3 perhaps i'm not sure
xxxx
2007-09-19 13:47:13 · answer #6 · answered by yeahpussycat 3 · 0⤊ 2⤋
[sqrt(3)][]-2 sqrt(3)]
=-2*3
=-6. ANS.
2007-09-19 13:48:00 · answer #7 · answered by Anonymous · 1⤊ 0⤋
sqrt(3)*[-2sqrt(3)] = sqrt(3)*(-2)*sqrt(3)
sqrt(3)*sqrt(3)*(-2) = 3*(-2) = -6
2007-09-19 13:46:57 · answer #8 · answered by grompfet 5 · 1⤊ 0⤋
sq rt(3)*{-2sq rt(3)}
(-2)*{sq rt(3)*sq rt(3)}
or (-2)*{sq rt(3^2)}
or -(2)*3
=-6 ans
2007-09-19 14:11:10 · answer #9 · answered by MAHAANIM07 4 · 0⤊ 1⤋
sqrt3*-2sqrt3=-sqrt3
2007-09-19 13:47:28 · answer #10 · answered by Anonymous · 0⤊ 2⤋