How do you find the horizontal asymptotes of x^5 - 4x^2 + 4?

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How do you find the horizontal asymptotes of x^5 - 4x^2 + 4?

2007-09-19 06:28:33 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

2 answers

Horizontal asymptotes happen when the derivative is zero.

f(x) = x^5 + 4x^2 + 4 so f'(x) = 5x^4 + 8x = x(5x^3 + 8)

f'(x) = 0 for x=0 and x = -curt(8/5) (that's cubic root). That's where the horizontal asymptotes are.

2007-09-19 06:33:37 · answer #1 · answered by Christophe G 4 · 0⤊ 1⤋

There are none.

2007-09-19 13:52:31 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋