Help needed!!!!!?

Question

Small spacecraft travelling in deep space. Not subject to gravitational field

the craft is moving at constant velocity = 250 m/s
in the positive x direction. It fires a thruster for a period of 10 s during which time it gives the spacecraft a constant acceleration of 7 ms^-2 in the negative x direction.
What is the velocity of the craft at the
end of this time (I got v = 180 m/s)

A 2nd thruster is fired which gives the craft a constant acceleration of 12 ms^-2 in the + y direction

1. How long will the 2nd thruster have to fire in order
that the speed of the space craft should reach 300 m/s

2. In what direction is the spacecraft travelling
when this speed is attained

Answer 1

1. is a Pythagorean question. (Where were you when he was covering this?) You have vx=180 and sqrt(vx^2+vy^2) = 300, so vy = 240. (It's a 3-4-5 triangle.) The time required = dv/a = 240/12.
2. Its angle from straight ahead = arctan(vy/vx) in the +y direction.