i need help with math?

Question

first i need to use the distributive property to rewrite each expression.....
1. 5(2x + 7)
2. 6x - 6y
3. 3(m + n)
4. 3p - 3q

and i need to know if when you are adding things up do you add the exponents up or keep them the same
example: 3x to the second power plus 2x to the second power......would it be 5x to the second power or 5x to the fourth power??

Answer 1

no, 3x to the second power + 2x to the second power is not 5x to the fourth power. it is:
3x to the second power + 2x to the second power.

that's it. only when you know what x is, then can you add them together, after finding the total for each.

1. 5(2x+7) = (5 x 2x) + (5 x 7) = 10x + 35
2. 6x - 6y = 6(x-y)
3. 3(m+n) = (3 x m) + (3 x n) = 3m + 3n
4. 3p - 3q = 3(p-q)

Answer 2

1. 5(2x + 7)
2. 6x - 6y
3. 3(m + n)
4. 3p - 3q


To rewrite each:

1. 5(2x + 7)= 10x + 35  here you multiply each term by 5
2. 6x - 6y= 6 (x-y)  here you factor out the 6
3. 3(m + n)= 3m +3n here you multiply each term by 3
4. 3p - 3q= 3(p-q) here you factor out the 3

3x to the 2nd power plus 2x to the 2nd power= 3x^2 + 2x^2= 5x^2 (three x squared plus 2 x squared equal 5 x squared.


You add the coefficient of like terms,

Answer 3

You add like amounts 5xsquared.
#1 you multipy the five times each amount in the parenthesis 10x +35 = 5(2x+7)
#2 your going to pull the 6 out 6(x-y) = 6x-6y
#3 like #1
#4 is like #2
When I was in your stage of alegebra I made a list of the rules-the last page in my notebook. Usually there is one or two a chapter and then however that affects 0. That way when you forget a rule you just go down the list. The list for the entire year didn't take up one page. Algebra builds so to cram for a test, you just go down the list-and do all of your homework yourself.

Answer 4

1. 5(2x+7) = (5 x 2x) + (5 x 7) = 10x + 35
2. 6x - 6y = 6(x-y)
3. 3(m+n) = (3 x m) + (3 x n) = 3m + 3n
4. 3p - 3q = 3(p-q)

Answer 5

1) 10x + 35
2) 6(x-y)
3) 3m + 3n
4) 3(p-q)

it becomes 5x to the second power. since they have the same variables (which is x to the second power), all you have to do is add the constants. x to the second power is different to x to the first power or x to the third power or x.

Answer 6

Your question is not so clear................