what is oxidation state of Pb in PbO2?

Answer 1

It is Pb+4

Two oxygens at 2- each is a total of 4- so we need a +4 charge for lead to get a neutral compound.

Answer 2

Oxidation States Of Lead

Answer 3

Here are some tips to find the oxidation number of a particle:
1)The oxidation number(ON) of an element is 0.
2)The ON of a sample ion is the same as the charge of the ion.
3)The total ON of a compound is naught.
4)The total ON of a complex ion is equal to the charge of the ion.
Below are some usual ON of elements in compound:
Element Usual ON in compound
Group1 +1
Group2 +2
Group3 +3
Group17 -1
Group16 -2
Oxygen -2
Hydrogen +1
In this case, you are required to determine the oxidation number of Pb in PbO2.
So, according to the tips given, the 3rd one states that the total ON of a compound is 0.
Therefore,
PbO2=0
Let Pb as x, O=-2
PbO2=0
x+2(-2)=0
x-4=0
x=+4
Pb^4+ +(O^2-)2--->Pb02

Answer 4

the oxidation state of Pb is +4

Answer 5

First, there are some trouble-free (customary) regulations that could desire to be observed whilst assigning oxidation numbers: one million) For the atoms in a independent species (i.e. an remoted atom, a molecule, or a formula unit), the sum of each and every of the oxidation numbers is O. Ex: Fe(s) atom has an oxidation style of 0; the sume of the oxidation numbers of each and every of the atoms in Cl2 and C6H12O6 is 0; The sum of the oxidation numbers of the ions in MgBr2 is 0. 2) For the atoms in an ion, the sums of the oxidation numbers is comparable to the charge on the ion. Ex: The oxidation style of Cr interior the Cr+3 ion is +3. 3) In compounds, the group one million metals all have an oxidation style of +one million and the group 2 metals all have an oxidation style of +2. Ex: The oxidation style of Na in Na2SO4 is +one million. 4) In compounds, the oxidation style of fluorine is -one million. 5) In compounds, hydrogen has an oxidation style of +one million. 6) In maximum compounds, oxygen has an oxidation style of -2. 7) In binary compounds with metals, group 7 factors have an oxidation style of -one million, group 6 have an oxidation style of -2, and group 5 factors have an oxidation style of -3. Ex: The oxidation style of Br is -one million in CaBr2. So we could do an occasion: KClO4 in accordance to rule 3, the oxidation style of ok is +one million. in accordance to rule 6, the oxidation style of O is -2 and the completed for 4 O atoms is -8. For those 2 factors , nsthe total is +one million - 8 = -7. The oxidation style of Cl could desire to be +7 to grant an entire of 0 for all atoms in this formula unit. Make sense?

Answer 6

Positive 4, since oxygen is negative 2, 2 times -2 is -4, positive 4 and negative 4 is equals to zero which is your net charge. so... Pb is +4

Answer 7

the oxidation state of Pb in PbO2 is +2....The compound is named Lead(II) peroxide...and the oxidation of oxygen in a peroxide ion (O2,2-)is -1..if we let the oxidation of Pb as x...

x+2(-1)=0
x-2=0
x=+2