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3 answers

∫x/sqrt(1-x^2) dx
u = 1 - x^2
du = -2xdx

∫x/sqrt(1-x^2) dx
= ∫(-1/2)u^(-1/2) du
= -u^(1/2) + c
= -sqrt(1-x^2) + c

2007-09-18 19:27:03 · answer #1 · answered by gudspeling 7 · 0 0

That guy is correct. I forgot the C of course like usual.

2007-09-18 19:30:29 · answer #2 · answered by Bender[OO] 3 · 0 0

WHATT!!! You can't find it in an integral table??
Oh s.h.i.t!!!!!!!
Ohhhhhh....... fµck!!!!!!!!!!!!
You're actually gonna have to --THINK--
You poor, poor bastard...................

I'll give you a hint: the answer is in the form (g(x))^k + C
and write √(1 - x²) as (1 - x²)^(1/2) and you just might see it.

Doug

2007-09-18 19:29:50 · answer #3 · answered by doug_donaghue 7 · 2 1

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