6 - 5 ( - 3z + 3) = - 3 ( - 4z + 2 ) -9
First, remove the parentheses:
6 + 15z - 15 = 12z - 6 - 9
Collect similar terms in each side:
15z - 9 = 12z - 15
Collect all terms with z on the left side and those without in the right side:
15z - 12z = 9 - 15
Simplify:
3z = -6
Divide both sides by 3:
z = -2
2007-09-18 19:05:52
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answer #1
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answered by tangy 5
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6 - 5(- 3z + 3) = - 3(- 4z + 2) - 9
6 + 15z - 15 = 12z - 6 - 9
15z - 9 = 12z - 15
3z = - 6
z = - 2
Answer: z = - 2
Proof (plug z with - 2):
6 - 5(- 3[- 2] + 3) = - 3(- 4[- 2] + 2) - 9
6 - 5(6 + 3) = - 3(8 + 2) - 9
6 - 5(9) = - 3(10) - 9
6 - 45 = - 30 - 9
- 39 = - 39
2007-09-18 19:16:57
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answer #2
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answered by Jun Agruda 7
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6 - 5 ( - 3z + 3) = - 3 ( - 4z + 2 ) -9
6 + 15z - 15 = 12z - 6 - 9
15z - 9 = 12z - 15
15z - 12z = 9 - 15
3z = -6
z = -6/3
z = -2
2007-09-18 19:10:31
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answer #3
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answered by Christine P 5
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6 - 5 ( - 3z + 3) = - 3 ( - 4z + 2 ) -9?
6-5(-3z+3)=21+15z, -3(-4z+2)-9=12z-15
21+15z=? 12z-15
21+15=12z-15z
36=-3z
-36=3z
z=-12
if z is equal to -12 your two equation is equal but if z is not equal to -12 then your two equations are not equal.
2007-09-18 19:07:29
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answer #4
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answered by CJF16 3
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6-5(-3z+3) = -3(-4z+2)-9
6+15z-15 = 12z-6-9
15z-9 = 12z-15
15z-12z =9-15
3z = -6
z = -2
2007-09-18 20:09:50
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answer #5
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answered by bach 2
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6 +15z - 15 = 12z - 6 - 9
15z - 9 = 12z - 15
3z = -6
z = -2
Always check your answer.
6 -5(-3(-2) + 3) = -3(-4(-2) + 2) - 9
6 -5(6 + 3) = -3(8 + 2) - 9
6 - 5(9) = -3(10) - 9
6 - 45 = -30 - 9
-39 = -39
2007-09-18 19:13:05
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answer #6
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answered by duffy 4
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Multiply 2 to 3x+3y+2z=-3 so that's going to become 6x+6y+4z=-6 you may now use removal (do away with z) 5x-2y-4z=-3 + 6x+6y+4z=-6 -------------------------- 11x+4y= -3 Multiply 3 to 3x + 3y + 2z = -3 so that's going to become 9x+9y+6z= -9 Multiply 2 to -2x+5y+3z=3 so that's going to become -4x+10y+6z=6 I did this so which you will do away with z lower back 9x+9y+6z= -9 - -4x+10y+6z= 6 --------------------------- 13x -y = -15 you on the on the spot have 2 equations 13x - y = -15 ----a 11x + 4y = -3 ----b Isolate y in equation a and substitute it to equation b y = 13x + 15 11x + 4(13x+15) = -3 11x + 52x +60 = -3 63x = -sixty 3 x= -one million substitute this to equation a y = thirteen(-one million) +15 y= 2 substitute the values of x and y to -2x + 5y +3z=3 -2(-one million) + 5(2) + 3z =3 2 + 10 + 3z =3 12 + 3z =3 3z = -9 z = -3 as a result, x =-one million y=2 z= -3 to verify the suggestions, substitute this values to those 3 equations and the equation ought to prefer to be certainly :D prefer this helps :D
2016-12-17 04:57:41
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answer #7
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answered by klohs 4
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6-5(-3z+3) = -3(-4z+2)-9
6+15z-15 =12z-6-9
15z-12z = -15-15
3z=0
z-0
2007-09-18 19:08:47
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answer #8
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answered by pol_1121 2
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6+15z-15 = 12z-6-9
15z - 9 = 12z - 15
15z - 12z = -15 + 9
3z = -6
z = -6/3
z = -2
hop it helps
2007-09-18 19:04:59
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answer #9
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answered by sweet_girlie 2
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6 + 15z - 15 = 12z - 6 - 9
15z - 9 = 12z - 15
3z = - 6
z = - 2
2007-09-18 20:38:21
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answer #10
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answered by Como 7
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