A user here said in the 1st Round , the wild card can never play a team that's in the same division. True? False? _I never knew that! What's the rationale behind this rule?
2007-09-18 18:56:48 · 5 answers · asked by Allergic To Eggs 6 in Sports ➔ Baseball
And so does the wild card then have to play the team with the best record outside their division?? i have to admit sometimes it gets a little confuzzling to me
2007-09-18 19:01:24 · update #1
Correct, a wild card team cannot play a team in the same division. The wild card team would play the team with the most wins of the other two division winners.
2007-09-18 19:08:15 · answer #1 · answered by jefflasvegas 2 · 2⤊ 1⤋
True. Look at the AL at the moment. Currently the Boston Red Sox have the best record in the AL, and the New York Yankees hold the wild card spot. If the playoffs were to begin today, the Yankees would go to Cleveland, and Boston would be hosting the Angels. Wild card teams are not to play their division winner in the first round.
Currently the standings are after 09/18/07:
1.Boston 90-62
2.Cleveland 89-62
3.Anahiem 89-62(tie breaker goes to Cleveland, won the head to head with Anahiem)
4.Yankees 87-64, have a 4.5 game lead on Det for the wild card.
2007-09-18 20:27:29 · answer #2 · answered by Anonymous · 3⤊ 0⤋
Its not as confusing as you think=).....so the wild card winner does not face the same team in the division..but the team with the best record....the dodgers last year made it by being a wild card team and they faced the NY mets .....and you can find more info at mlb.com or any other sport stations.....hope this is less confusing...srry if it isnt........GO BASEBALL!!!!!!!!..WOOHOO
2007-09-18 19:11:54 · answer #3 · answered by smart 1 4 · 1⤊ 0⤋
Yes, the wildcard team never matches up with the champion of its own division.
2007-09-18 19:08:46 · answer #4 · answered by Chipmaker Authentic 7 · 2⤊ 0⤋
It is true but I believe it's just for the 1st round.
2007-09-18 20:18:13 · answer #5 · answered by Anonymous · 1⤊ 0⤋