Here is the problem:
10.2/0.3 Divided By: 1.7/.1
The "/" represents the fraction
2007-09-18 17:41:54 · 9 answers · asked by Dude 4 in Education & Reference ➔ Homework Help
I know how to use a calculator, and I pay attention. Don't tell me you all are perfect.
2007-09-18 17:50:15 · update #1
=2
34/17
2007-09-18 17:46:37 · answer #1 · answered by Edgar R 4 · 0⤊ 0⤋
Since it has been awhile since I have done decimal fractions, let's hope this is right:
10.2/0.3 divided by 1.7/.1 =
10.2/0.3 times .1/1.7 =
(multiply each, numerator and denominator to come up with) : 1.02/.51
Reduce down to equal 2.
2007-09-18 17:53:12 · answer #2 · answered by jan51601 7 · 0⤊ 0⤋
Just flip the second fraction over and mulitiply by the recipricol. Then factor out the numbers.
10.2/0.3 X .1/1.7
10.2/ 1.7 factors out to six. while 1.7 factors to one. so here
10.2 /1.7/0.3 X .1/1.7/1.7.
6/0.3 X .1/ 1
Now you multiply the numerator and demoniator and then simplify.
.6/0.3 or 2
Also if you didn't know, a fraction is simply a number that divides another number. Like 10.2/0.3 is simply 10.2 divided by 0.3
2007-09-18 17:49:36 · answer #3 · answered by narutoneopetanimelove 3 · 0⤊ 0⤋
10.2/3 divided by 1.7/1
3.4 (10.2 divided by 3) divided by 1.7 = 2
the answer is 2.
2007-09-18 17:55:18 · answer #4 · answered by V B 5 · 0⤊ 0⤋
(10.2/0.3) / (1.7/0.1)
Multiply both fractions by [(0.3)(0.1)] so that the bottom halves of each fraction cancel out.. You're left with:
=(10.2*0.1)/(1.7*0.3)
=1.02 / .51
=2
2007-09-18 17:48:03 · answer #5 · answered by Angels Always 1 · 0⤊ 0⤋
Wow. It's amazing how much paying attention in class and reading the book might help you.
2007-09-18 17:46:15 · answer #6 · answered by joecon113 3 · 0⤊ 2⤋
invert the second fraction and mutiply straight across.
2007-09-18 17:45:37 · answer #7 · answered by huckleberry 5 · 0⤊ 0⤋
200...you have to cross multiply
2007-09-18 17:44:51 · answer #8 · answered by skeezbucket 4 · 0⤊ 0⤋
boy, your answer is 2...learn to use a calculator
2007-09-18 17:47:30 · answer #9 · answered by gwen47454 2 · 0⤊ 1⤋