The area of a rectangle is 18 square inches. The length of the rectangle is twice its width. Find the length and width of the rectangle.
2007-09-18 17:41:45 · 8 answers · asked by Anne 4 in Science & Mathematics ➔ Mathematics
L = length
W = width
L = 2W
L W = 18
2 W ² = 18
W ² = 9
W = 3
L = 6
Length = 6 ins
Width = 3 ins
2007-09-19 22:39:57 · answer #1 · answered by Como 7 · 2⤊ 0⤋
Let w be the width of the rectangle. Since the length is twice the width, then the length is 2w.
Now, the area of a rectangle is determined by the product of its width and length, so:
A = (2w)w
A = 2w^2
Since the area is 18 square inches, then:
18 = 2w^2 or 2w^2 = 18
w^2 = 9
w = +3 or -3.
But width cannot be negative, so we only take w = +3.
Therefore, the width of the rectangle is 3 inches and the length is 2w = 6 inches.
2007-09-19 00:49:52 · answer #2 · answered by tangy 5 · 0⤊ 0⤋
Area of rectangle = length * width
A = l * w
18 = 2w * w
18 = 2w^2
18/2 = w^2
9 = w^2
3 = w
width = 3 inches
length = 2 * width or 2w= 2*3 = 6 inches
2007-09-19 00:49:27 · answer #3 · answered by UJ 3 · 0⤊ 0⤋
W x (2 x W) = 18
2W(squared) = 18
W(squared) = 9
W = 3
L = 2 x 3
L = 6
2007-09-19 00:51:20 · answer #4 · answered by ? 2 · 0⤊ 1⤋
w(2w) = 18
2w^2 = 18
w^2 = 9
w = 3 (can't be -3 because it's a length)
l = 6
2007-09-19 00:46:19 · answer #5 · answered by ccw 4 · 0⤊ 0⤋
area = length * width
18=2w*w
18=2w^2
9=w^2
w=3
width=3
length=6
2007-09-19 00:50:57 · answer #6 · answered by princess 3 · 0⤊ 0⤋
L= 6
W= 3
A= 18
2007-09-19 00:46:28 · answer #7 · answered by da ndn dude 2 · 0⤊ 0⤋
christine + huy = 557637
2007-09-19 00:49:09 · answer #8 · answered by Huy 2 · 0⤊ 1⤋