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Find the rate of change of the volume of a cube with respect to the length s of a side. What is the rate when s = 4?

2007-09-18 17:33:30 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

v = s^3
so v' = 3s^2
plug in 4
3(4)^2 = 3(16) = 48

2007-09-18 17:39:22 · answer #1 · answered by ccw 4 · 1 0

V = s³
dV/ds = 3s² = 48 cubic units per unit when s = 4 units

2007-09-19 00:42:05 · answer #2 · answered by Anonymous · 1 0

Take thee derivative of v=s^3 and get
dv/ds = 2s²
At s=4 the rate is 2*4² = 32:1

Doug

2007-09-19 00:40:27 · answer #3 · answered by doug_donaghue 7 · 0 2

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