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Ok, so i need to simplify this but i don't know how to do it. I need all the steps so i can do the rest easily.

3 (xsquared - 3 + 4x - 3) +2 (xsquared + 5)

2007-09-18 16:56:24 · 7 answers · asked by Whatsupbaby? 2 in Education & Reference Homework Help

7 answers

3(x^2-3+4x-3)+2(x^2+5)
3x^2-9+12x-9+2x^2+10


5x^2+12x-8

2007-09-18 17:53:03 · answer #1 · answered by Edgar R 4 · 0 0

u have to do the distributive property. Do you know what that is right?
well to help multipy 3 by each thing in the first parentheses. For Ex
3 x Xsquared would = 3xsquared

understand? the you would multiply the three by the other things in parentheses.

Next. you would multiply 2 by watever is in the parentheses. and then combine like terms and simplify ^_^ hope this helped. if you dont understand it still or u need more help, email me

sparklin_beyb@yahoo.com

2007-09-18 17:18:33 · answer #2 · answered by Anonymous · 0 0

3(x^2 - 3 + 4x - 3) + 2(x^2 + 5)
Multiply through (distributive property)
3x^2 - 9 + 12x - 9 + 2x^2 + 10
Add like terms
5x^2 + 12x -8

Unable to factor. This is the simplest form. Doublecheck to make sure you wrote it down right. The -3 twice is weird.

2007-09-18 17:09:38 · answer #3 · answered by gitter1226 5 · 0 0

Distribute the problem turning into simpler form
(3)x^2- 3(3) + 4x(3) - 3(3) +(2)x^2 + 5(2)
Turns into
3x^2 - 9 + 12x - 9 + 2x^2 + 10

Then elminate common terms.

3x^2-2x^2-9+12x - 9 + 2^2-2x^2 + 10=

x^2- 9+12x - 9+ 10=

You can probably figure out the rest.

2007-09-18 17:06:46 · answer #4 · answered by narutoneopetanimelove 3 · 0 1

simplify the terms first, so x^2+4x-6

multiply 3 into that to get 3x^2+12x-18
do the same for the other part to get 2x^2+10
combine like terms
5x^2+12x-8

2007-09-18 17:06:39 · answer #5 · answered by Anonymous · 0 0

order of operations multiply 3x squared -9+12x-9+2xsquared+10= 7xsquared+12x-13

2007-09-18 17:14:30 · answer #6 · answered by Jackie C 3 · 0 1

giving you the answer isn't helping you at all. you should tell your teacher you need help understanding

2007-09-18 17:04:22 · answer #7 · answered by Stephen 3 · 0 0

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