Cisplatin is
K2PtCl4 (aq) + 2NH3 (aq) ---> Pt(NH3)2 Cl2 (s) + 2KCl (aq)
[FYI, Cl is chlorine]
What mass of cisplatin can be made from 100g of K2PtCl4 and sufficient NH3? What mass of KCl is also produced?
I tried converting 100g K2PtCls to moles then to NH3 moles and then to g NH3.
I don't know how to do this problem. :(
Help? Step by step please. Thank you very much! :)
2007-09-18 16:38:42 · 3 answers · asked by v 2 in Science & Mathematics ➔ Chemistry
It says sufficient NH3, which means it is in excess.
Convert your K2PtCl4 to mols and multiply against ratio of product, in this case 1 to 1 Then you need to get mass of product and multiply by mols./ratio
Ignore NH3, as it is not the driver of this reaction. K2PtCl4 is limiting and drives the reaction.
Looks like this.
100g K2PtCl4 X 1mol/ grams of K2PtCl4 X 1mol Pt(NH3)2/1mol K2PtCl4 X Grams Pt(NH3)2/1mol Pt(NH3)2
2007-09-18 16:47:37 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The previous answer is correct about ammonia.
Step 1. Find mol wt of K2PtCl4.
Step 2. Divide 100g by mol wt, call answer "A"
Step 3. Find mol wt of Pt(NH3)2Cl2 [1mole-1mole rxn]
Step 4. Multiply this mole wt by "A" mass cisplatin
Step 5. Find mol wt of KCl
Step 6. Multiply this mole wt by "2A" [1 mole-2 mole rxn] mass KCl
2007-09-18 16:58:34 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
properly, in case you probably did it this form, then that is suited: convert grams to moles locate the mole ratio of nitrogen monoxide to ammonia. considering the fact which you decide on contraptions to cancel out, placed NO on the backside.
2016-12-26 17:41:45 · answer #3 · answered by humphries 4 · 0⤊ 0⤋